The Time and Distance are very important concepts for any Indian competitive exams, where aptitude test conducted with time and distance concepts. observing since 2013 onwards, all the Bank and public and private sectors are conducting aptitude exams with time and distance.

Today we are discussing with basics of time and distance concepts in details.

**What are Time and Distance.?**

### Time:

The time is processed to estimate the amount of work done, anyone can easily estimate time within seconds but whenever it amount work is done in more than a day or days then it difficult to estimate it.

### Distance:

A distance is from one location to another location, where it counts in number of meters, kilometers(KM),Â

- Distance = Speed x Time
- Time = Distance/Speed
- Speed= Distance/Time

There are three relative words Speed, Time and Distance are involved to calculate above factors.

*Speed, Time and Distance:*

Speed = Distance , Time = Distance , Distance = (Speed x Time). Time Speed *km/hr to m/sec conversion:*

*x*Â km/hr =*x*Â x5 m/sec. 18 *m/sec to km/hr conversion:*

*x*Â m/sec =*x*Â x18 km/hr. 5 **If the ratio of the speeds of A and B isÂ**Â :*a***Â**the*b*, then the ratio of

the times taken by then to cover the same distance is 1 : 1 orÂ *b*Â :Â*a*.*a**b***Suppose a man covers a certain distance atÂ**at*x*Â km/hr and an equal distance**Â***y*Â km/hr. Then,

the average speed during the whole journey is 2 *xy*km/hr. *x*Â +Â*y*

### Examples#1:

A Donkey crosses a 300 m long street in 5 minutes. What is donkey speed in km per hour?

a. 3.6Â Â b. 7.2Â Â c.9.3Â Â d.6.5

**Solution:**

Speed = | 300 | m/sec. | |

5 x 60 |

Â Â = 1 m/sec.

Converting m/sec to km/hr

Â Â = | 1 x | 18 | km/hr | ||

5 |

Â Â = 3.6 km/hr.

### Examples#2:Â

If a dog walks at 10 km/hr instead of 5 km/hr, he would have walked 50 km more. How much ditance travelled by the dog is,

A. 50KMÂ Â B.25KMÂ Â c. 44KMÂ Â d. 32KM

**Solution:**

The given data is dog walks 10 km/hr instead of 5 km/hr and dog walked 50 km.

Let the original distance travelled beÂ *x*Â km.

Then, | x |
= | xÂ + 50 |

5 | 10 |

Â 10*x*Â = 5*x*Â + 25

Â 1*x*Â = 25

Â *x*Â = 25 km.

### Example#3:

A Karthik traveled a distance of 30 km in 5 hours. He travelled partly on foot @ 4 km/hr and partly on bicycle @ 5 km/hr. The distance traveled on foot is:

A. 10 KMÂ Â B 20KMÂ Â C. 30KMÂ Â 4.40KM

**Solution:**

Karthik traveled distance on foot beÂ *x*Â km.

Then, distance traveled on a bicycle = (30 –*x*) km.

So, | x |
+ | (30 –x) |
= 5 |

4 | 5 |

Â 5*x*Â + 4(30 –*x*) = 5 x 20

Â 1*x*Â = 20

Â *x*Â = 20 km.

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